Monday, September 30, 2019

Workplace Violence

Workplace violence is present in every nook and cranny of corporate America, affecting millions of Americans every year. Workplace violence is defined by the Occupational Safety & Health Administration, OSHA, as any act or threat of physical violence, harassment, intimidation, or other threatening disruptive behavior that occurs at the work site. It ranges from threats and verbal abuse to physical assaults and even homicide. In 2011, there were over 2 two million reports and claims of workplace violence, with 458 being homicides1. Workplace violence is at the forefront of everyone’s mind when a breaking news story is broadcast on the evening news, such as the recent shootings in Santa Cruz, California by a disgruntled ex-cop, and the Sandy Hook Elementary School shooting in Newtown, Connecticut, but workplace violence can strike anywhere and at any time, and is a major concern for employers and employees across America. There are different types of workplace violence, which can be categorized as follows: (1)violence by outsiders or nonemployees, usually in the attempt of a crime, such as robbery or shoplifting, (2)violence by a customer or a client, such as a student or a patient, (3)violence by employees and former employees, and (4)violence by domestic partners, such as boyfriends/girlfriends and husbands/wives. Such categorization can help in coming up with ways to prevent workplace violence since each type of violence requires a different approach to prevention, and certain workplaces and environments may be at higher risk for certain types of violence. Although workplace violence can seem very random, there are certain industries and job categories that are more susceptible to violence than others. According to OSHA, certain factors can increase the risk of violence in the workplace, such as exchanging money with the public, working with unstable people, and working where alcohol is served1. People working in certain establishments, such as retail stores and bars, are at increased risk of violence. Professions in law enforcement, healthcare, public service workers and those who work alone or in small groups are at greatest risk of violence. Manager’s role in identifying and reporting workplace violence. Every employee of an organization is responsible for providing a safe and secure environment to work in, and thus should be knowledgeable about workplace violence and be ready to act in advance to reduce the threat of violent incidents. Managers especially have a big duty to make sure that the work environment of their employees has minimal stress triggers, and that the department culture is one that is friendly and open, ensuring that employee safety is valued. Managers should follow their progressive discipline policy when addressing concerns with employees to prevent violent reactions by employees who feel that they have been treated unfairly. Managers should also treat their employees with respect and decency, especially when disciplining or firing them, as depriving an employee of dignity in front of other employees can trigger violent behavior. Most importantly, managers need to be trained on what clues to look for, and how to handle certain situations when confronted with warning signs of workplace violence by employees. This will allow managers and subordinates to know the warning signs and report them to management accordingly. Sure there are people that suddenly ‘snap’ and go off the deep end, but in most instances of workplace violence, there are certain signs of trouble that are exhibited by the perpetrator. According to Dr. Lynne McClure, an expert in managing high-risk employee behaviors before they escalate to workplace violence, there are always warning signs involving workplace violence2. She puts these eight warning signs in the following categories: †¢Actor behaviors – employees act out their anger by yelling and shouting †¢Fragmentor behaviors – employees take no responsibility for their actions and blames others for their mistakes †¢Me-First behaviors – employees act selfishly without regard to fellow coworkers †¢Mixed-Messenger behaviors – employees talk positively but behave negatively †¢Wooden-Stick behaviors – employees are not receptive to change, and are inflexible and controlling †¢Escape-Artist behaviors – employees compulsively lie and rely on negative stress relievers such as drugs and gambling †¢Shocker behaviors – employees suddenly act in ways that are out of character †¢Stranger behaviors – employees are remote and have poor social skills, and become fixated on an idea and/or an individual. There is no standard ‘profile’ of a person who commits workplace violence, and by no means is someone a threat just because they display one of these traits. Employees that exhibit many of these traits, and with increasing intensity, may be a danger and may need some help. Being able to identify these signs and warning signals, and reporting it to management timely can help prevent a workplace violence incident. HR’s role in managing and preventing workplace violence. Every reasonable employer wants to keep employees safe from workplace violence, but according to the Bureau of Labor Statistics, less than 30% of employers have a violence prevention policy in place3. Outlined below are some things that a human resource department can implement to mitigate workplace violence. †¢Violence Prevention Policy – First and foremost, every company should implement a zero-tolerance policy against workplace violence, which clearly defines what workplace violence is, and the company’s position on it. The policy must clearly outline which behaviors and actions are acceptable and which are unacceptable. The policy should state that violence of any kind is not tolerated and is grounds for immediate termination. †¢Training – Training for managers and employees to ensure that they know the warning signs for violence is critical. There are many signs that can point to indications of imminent violent, so training the employees to recognize the warning signs can help stop a violent act by identifying the individual and providing assistance before a violent act is committed. Each and every employee is responsible for creating a safe working environment, and it is HR’s job to help employees get the training necessary to manage a safe workplace. †¢Hiring, retaining and firing – HR plays a critical role in preventing violence in the workplace with its hiring, retention and firing practices. Usually, past behavior can predict future behavior, so it is important that the HR department screen potential new hires carefully. One way to avoid workplace violence is by not hiring people who exhibit violent behavior. Thus, the HR department must conduct thorough background checks on all potential new hires. Companies should make it a general policy to run background checks on all applicants before hiring them. HR departments must make a concerted effort to carefully screen all potential new hires by scrutinizing information on resumes and conducting reference checks. Also, HR can help prevent workplace violence by rooting out trouble-makers early. Retaining employees who have had behavioral issues in the past can expose a company to workplace violence and litigation. The HR department needs to be proactive with helping to identify employees that pose a potential danger thru through analysis of past work records. For example, if an employee has had issues with making threats or getting into confrontations with coworkers in the past, immediate ction may need to be taken before any major incident occurs. Finally, HR plays a big role in creating a peaceful environment when handling employee terminations. When an employee gets terminated, it is a very stressful event for the employee, and ca n push him/her over the edge. In order to ease the stress and alleviate some of the pressures on the employee being terminated, the HR department can help the situation by being compassionate and clearly explaining the reasons for the termination and allowing an opportunity to the employee to discuss any disagreement with the termination. Also, the HR department can provide placement or counseling services. Provide an employee assistance program (EAP) – there are many reasons that someone resorts to violence in the workplace, but some stem from issues outside of the workplace, such as relationship issues, financial troubles, or substance abuse problems. Employing an EAP can provide help to employees before a serious incident manifests itself in the workplace. Through the use of an EAP, employees can help manage their issues by coordinating with an objective, third party. All types of services should be offered, including counseling, anger management classes and rehabilitation services. Financial Impact of Workplace Violence – Calculating the Cost Workplace violence is real, and with it comes real costs. The actual cost of workplace violence is hard to calculate, but per the National Institute for Occupational Safety and Health, NIOSH, a division of the Center for Disease Control, it is estimated that workplace violence costs American businesses $121 billion a year4. This takes into account many factors, including costs due to lost productivity, loss of sales, increase in insurance premiums, litigation costs, lost time and absenteeism, workers’ compensation claims, medical claims, management distractions, negative PR, and organizational change initiatives. According to the Bureau of Justice Statistics5: †¢About 500,000 victims of violent crime in the workplace lose an estimated 1. 8 million workdays each year. This represents a $55 million impact as a result of loss of productivity and increased healthcare expenses †¢Domestic violence costs businesses approximately $6 billion annually in healthcare costs, lost productivity, and missed work time †¢The average out-of-court settlement for ‘negligence’ litigation is approximately $500,000 and the average jury award is around $3 million †¢For 6 to 18 weeks after an incident, there is a 50% decrease in productivity and a 20% to 40% turnover in employees The cost of recovery after a catastrophic, workplace violence incident is astronomical, so it is in every company’s best interest to put in place the necessary preventive measures to avoid such incidents from happening in the first place. Unfortunately, most companies are reactive instead of proactive, so the costs associated with workplace violence may be viewed as the cost of doing business, big business at that. Everyone plays a role in preventing workplace violence. Even with workplace violence receiving increased attention, there is much work that needs to be done to understand the causes and potential solutions. Management, front line employees and the HR department must work together collectively to prevent the next workplace violence incident. The best practices set forth must be implemented and adhered to with perfection. A company can’t guarantee that a violent act will never happen between their four walls, but there are preventive measures that can be taken to improve the chances of avoiding a workplace violence incident.

Surface Areas and Volumes

Question Bank In Mathematics Class X (Term–II) 13 SURFACE AREAS AND VOLUMES A. SUMMATIVE ASSESSMENT (c) Length of diagonal = TH G (a) Lateral surface area = 4l2 (b) Total surface area = 6l2 (c) Length of diagonal = 3 l 3. Cylinder : For a cylinder of radius r and height h, we have : (a) Area of curved surface = 2? rh BR O ER 2. Cube : For a cube of edge l, we have : O YA L TEXTBOOK’S EXERCISE 13. 1 Unless stated otherwise, take ? = 22 . 7 Q. 1. 2 cubes each of volume 64 cm3 are joined end to end. Find the surface area of the resulting cuboid. [2011 (T-II)] 1 S l 2 ? b2 ? h2 5. Sphere : For a sphere of radius r, we have : Surface area = 4? 2 6. Hemisphere (solid) : For a hemisphere of radius r we have : (a) Curved surface area = 2? r2 (b) Total surface area = 3? r2 PR (a) Lateral surface area = 2h(l + b) (b) Total surface area = 2(lb + bh + lh) (d) Total surface area of hollow cylinder = 2? h(R + r) + 2? (R2 – r2) 4. Cone : For a cone of height h, radius r and sla nt height l, we have : (a) Curved surface area = ? rl = ? r h 2 ? r 2 (b) Total surface area = ? r2 + ? rl = ? r (r + l) Sol. Let the side of cube = y cm Volume of cube = 64 cm3 Then, volume of cube = side3 = y3 As per condition ? y3 = 64 ? y3 = 4 3 AK AS HA 13. SURFACE AREA OF A COMBINATION OF SOLIDS 1. Cuboid : For a cuboid of dimensions l, b and h, we have : (b) Total surface area = 2? r2 + 2? rh = 2? r(r + h) (c) Curved surface area of hollow cylinder = 2? h(R – r), where R and r are outer and inner radii N Q. 3. A toy is in the form of a cone of radius 3. 5 cm mounted on a hemisphere of same radius. The total height of the toy is 15. 5 cm. Find the total surface area of the toy. [2011 (T-II)] Sol. Radius of the cone = Radius of hemisphere = 3. 5 cm Total height of the toy = 15. 5 cm ? Height of the cone = (15. 5 – 3. 5) cm = 12 cm Slant height of the cone (l ) = G O Diameter of the hollow cylinder = 14 cm 14 Radius of the hollow hemisphere = cm = 7 cm 2 ? Radius o f the base of the hollow cylinder = 7 cm Total height of the vessel = 13 cm ? Height of the hollow cylinder = (13 – 7) cm = 6 cm Inner surface area of the vessel = Inner surface area of the hemisphere + Inner surface area of the hollow cylinder = 2? (7)2 cm2 + 2? (7) (6) cm2 = 98 cm2 + 84 cm2 = (98 + 84) cm2 22 = 182? cm2 = 182 ? cm2 = 26 ? 22 cm2 7 = 572 cm2. PR AK = Q. 2. A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. The diameter of the hemisphere is 14 cm and the total height of the vessel is 13 cm.Find the inner surface area of the vessel. [2011 (T-II)] Sol. ? Diameter of the hollow hemisphere = (3. 5)2 ? (12) 2 cm = 156. 25 cm = 12. 5 cm Total surface area of the toy = Curved surface area of the hemisphere + Curved surface area of the cone = 2? (3. 5)2 cm2 + (3. 5) (12. 5) cm2 = 24. 5? cm2 + 43. 65 cm2 = 68. 25? cm2 = O TH ER YA L BR S Q. 4. A cubical block of side 7 cm is surmounted by a hemisphere. What is the greatest diameter the hemi sphere can have? Find the surface area of the solid. [2011 (T-II)] Sol. Side of cubical block = 7 cm Side of cubical block = Diameter of hemisphere = 7 cm ? R = 7 7 ? R = cm 2 Surface area of solid = Surface area of the cube – Area of base of hemisphere + C. S. A. of hemisphere 2 – ? R2 + 2? R2 = 6 ? side = 6 (7)2 cm2 + ? R2 22 7 7 2 = 6 ? 7 ? 7 cm2 + ? ? cm 7 2 2 7? ? = ? 6 ? 49 ? 11? ? cm2 2? ? 77 ? ? ? 588 ? 77 ? 2 = ? 294 ? ? cm2 = ? ? cm . 2? 2 ? ? ? r 2 ? h2 2 AS 665 cm2 = 332. 50 cm2 2 HA 68. 25 ? 22 cm2 = 214. 5 cm2. 7 ? y = 4 cm Hence, side of cube is 4 cm. For the resulting cuboid length (l ) = 4 + 4 = 8 cm breadth (b) = 4 cm height (h) = 4 cm ? Surface area of the resulting cuboid = 2(lb + bh + hl ) = 2(8 ? 4 + 4 ? 4 + 4 ? 8) cm2 = 2(32 + 6 + 32) cm2 = 2(80) cm2 = 160 cm2. N Q. 5. A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface are a of the remaining solid. Sol. Diameter of the hemisphere = l = Side of the cube = 45? mm2 + 25? mm2 = (45 + 25) mm2 = 70? mm2 22 = 70 ? mm2 = 220 mm2. 7 Hence, surface area of capsule = 220 mm2 O Q. 6. A medicine capsule is in the shape of a cylinder with two hemispheres stuck to each of its ends (see figure below). The length of the entire capsule is 14 mm and the diameter of the capsule is 5 mm.Find its surface area. TH ER YA L BR Sol. Diameter of capsule = Diameter of hemisphere = Diameter of cylinder = 5 mm 5 Radius of the hemisphere = r = mm 2 Height of the cylinder = [14 – (2. 5 + 2. 5)] mm = 9 mm Surface area of the capsule = Surface area of cylinder + 2 Surface area of hemisphere G O S = l2 ? ? ? 24 ? . 4 = 2? (2) (2. 1) m2 + (2) (2. 8) m2 = (8. 4? + 5. 6) m2 22 2 = 14? m2 = 14 ? m = 44 m2 7 ? Cost the canvas of the tent at the rate of Rs 500 per m2 = Rs 44 ? 500 = Rs 22000 Hence, cost of the canvas is Rs 22000. Q. 8. From a solid cylinder whose height is 2. 4 cm a nd diameter 1. cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid to the nearest cm2. Sol. Height of cylinder = 2. 4 cm Height of cone = 2. 4 cm Radius of cylinder = r = Radius of cone = 0. 7 cm Slant height, of the cone l= 3 PR ?l? ?l 2 2 ? 6l 2 = ? ? ? ? 6l = 4 ? 2? 2 Radius of the cylinder = 2 m Total surface area of the tent = Curved surface area of the cylinder + Curved surface area of the cone AK ?l? ?l? 2 = 2? ? ? ? 6l ? ? ? ? ? 2? ?2? 2 2 AS l 2 Surface area of the remaining solid = Surface area of hemisphere + Surface area of cube – Area of base of hemisphere ?Radius of the hemisphere = Q. 7. A tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are 2. 1 m and 4 m respectively and the slant height of the top is 2. 8 m, find the area of the canvas used for making the tent. Also, find the cost of the canvas of the tent at the rate of Rs 500 per m2 (note that the base of the tent will not be covered with canvas. ) Sol. Radius of the cone = 2 m ? ? 5? 2 ? ? 5? 2 2 = 2? ? ? (9) mm + 2 ? 2? ? ? ? mm ? 2? ? 2? ? ? ? ? (0. 7)2 ? (2. 4) 2 cm = 2. 5 cm HA 1. 4 cm = 0. 7 cm 2 N Q. 9.A wooden article was made by scooping out a hemisphere from each end of a solid cylinder, as shown in figure. If the height of the cylinder is 10 cm, and its base is of radius 3. 5 cm, find the total surface area of the article. Sol. Height of cylinder = 10 cm Total surface area of the remaining solid = C. S. A. of cylinder + C. S. A. of cone + Area of base = 2? rh + ? rl + ? r2 = ? r (2 h + l + r) 22 = ? 0. 7 ? (2 ? 2. 4 + 2. 5 + 0. 7) cm2 7 22 7 = ? (4. 8 + 3. 2) cm2 7 10 22 7 = ? ? 8. 0 cm2 7 10 176 = cm2 = 17. 6 cm2 10 Hence, total remaining surface area = 17. 6 cm2 = 18 cm2. Radius of cylinder = 3. cm Total surface area of the article = C. S. A of cylinder + 2 C. S. A. of hemisphere = 2? (3. 5 (10) cm2 + 2 [2? (3. 5)2] cm2 = 70 cm2 + 49 ? cm2 = (70 + 49) cm2 22 2 = 119? cm2 = 119 ? cm 7 = 17 ? 22 cm2 = 374 cm2. OTHER IMPORTANT QUESTIONS Q. 1. A cylindrical pencil sharpened at one edge is the combination of : (a) a cone and a cylinder (b) frustum of a cone and a cylinder (c) a hemisphere and a cylinder (d) two cylinders Sol. (a) The given shape is a combination of a BR O TH ER S PR AK Its surface area = 6 ? YA L AS Increase in surface area = ? Per cent increase = cone and a cylinder. G O Q. . If each edge of a cube is increased by 50%, the percentage increase in the surface area is : (a) 25% (b) 50% (c) 75% (d) 125% Sol. (d) Let the edge of the cube be a. Then, its surface area = 6a2 150a 3a New edge = = . 100 2 4 Q. 3. The total surface area of a hemisphere of radius 7 cm is : [2011(T-II)] (a) 447 ? cm2 (b) 239 ? cm2 (c) 147 ? cm2 (c) 174 ? cm2 Sol. (c) Total surface area of the hemisphere = 3? r2 = 3 ? ? 49 cm2 = 147? cm2 Q. 4. If two solid hemispheres of same base radius r are joined together along their bases, HA 9a 2 27a 2 = 4 2 27a 2 15a 2 – 6a2 = 2 2 15a 2 100 ? 2 = 125% 6a 2 N hen curved surface area of this new solid is : (a) 4? r2 (b) 6? r2 2 (c) 3? r (d) 8? r2 Sol. (a) The resulting solid will be a sphere of radius r. ? Its curved surface area = 4? r2. Q. 9. The total surface area of a top (lattu) as shown in the figure is the sum of total surface area of hemisphere and the total surface area of cone. Is it true? Sol. No, the statement is false. Total surface area of the top (lattu) is the sum of the curved surface area of the hemisphere and the curved surface area of the cone. Sol. (d) We have ? 2 6a1 2 6a2 a13 a2 3 = AS 4 64 a1 ? = 3 a2 27 HA Q. 5. Volumes of two cubes are in the ratio 64 : 27.The ratio of their surface areas is : (a) 3 : 4 (b) 4 : 3 (c) 9 : 16 (d) 16 : 9 Q. 10. Two cones with the same base radius 8 cm and height 15 cm are joined together along their bases. Find the surface area of the shape so formed. N 32 Sol. True. Since the curved surface area taken t ogether is same as the sum of curved surface areas measured separately. G O ?r r 2 ? h2 ? 2? rh . Is it true? YA L Q. 7. If a solid cone of base radius r and height h is placed over a solid cylinder having same base radius and height as that of the cone, then the curved surface area of the shape is BR . . . Radius of the hemispherical toy, r = 3. cm Curved surface area of the toy = 2? r2 22 =2? ? (3. 5)2 cm2 = 77 cm2 7 Total surface area of the toy = 3? r2 22 =3? ? (3. 5)2 cm2 = 115. 50 cm2. 7 O TH ER Q. 8. Two identical solid cubes of side a are joined end to end. Then find the total surface area of the resulting cuboid. Sol. The resulting solid is a cuboid of dimensions 2a ? a ? a. ? Total surface area of the cuboid = 2 (lb + bh + hl) = 2 (2a ? a + a ? a + a ? 2a) = 10a2. 5 S Q. 6. The diameter of a solid hemispherical toy is 7 cm. Find its curved surface area and total surface area. Sol. Diameter of the hemispherical toy = 7 cm. Q. 11. A tent of height 8. 5 m is in the form of a right circular cylinder with diameter of base 30 m and height 5. 5 m, surmounted by a right circular cone of the same base. Find the cost of the canvas of the tent at the rate of Rs 45 per m2. Sol. PR 22 ? 8 ? 17 cm2 7 = 854. 85 cm2 = 855 cm2 (approx. ) = 2 (? rl) = 2 ? Height of the tent = 8. 25 m. Height of the cylindrical part = 5. 5 m . . . Height of the conical part = (8. 25 – 5. 5) m = 2. 75 m. 30 Base radius of the tent = m = 15 m. 2 . . . Slant height of the conical part (15)2 + (2. 75)2 m = = 15. 25 m. = AK = 42 16 = = 16 : 9 9 Sol. Slant height of each cone = 82 ? 152 cm 64 ? 225 cm = 17 cm. ? Surface area of the resulting shape 225 + 7. 5625 m Curved surface area of the tent = curved surface area of the cylindrical part + curved surface area of the conical part = 2? rh + ? rl = ? r (2h + l) 22 = ? 15 (2 ? 5. 5 + 15. 25) m2 7 ? 22 ? = ? ? 15 ? 26. 25? m 2 ? 7 ? = 1237. 50 m2. Rate of the canvas = Rs 45 per m2 . . . Cost of the canvas = Rs (1237. 50 ? 45) = Rs 55687. 50. Sol. Slant height of the cone = = = AS and height of the cone = 14 cm BR = 22 ? 7 ( 7 5 + 7) cm2 7 O TH = 7 ? 14 cm = 245 cm = 7 5 cm. Total surface area of the cone = ? rl + ? r2 = ? r (l + r) 2 2 ER Slant height of the cone = r 2 ? h2 = 154 ( 5 + 1) cm2 Surface area of the cube = 6 ? 142 cm2 = 1176 cm2 ? Surface area of the remaining solid left out after the cone is carved out = surface area of the cube – area of base of the cone + curved surface area of the cone 22 2 ? ? = ? 1176 ? ? 7 ? 154 5 ? cm2 7 ? ? YA L = ? 1022 ? 154 5 ? cm2. ? ? Q. 13. A toy is in the form of a cone mounted on a hemisphere of common base radius 7 cm. The total height of the toy is 31 cm. Find the total surface area of the toy. [2007, 2011 (T-II)] 6 G O S Q. 14. A solid is in the form of a right circular cylinder with hemispherical ends.The total height of the solid is 58 cm and the diameter of the cylinder is 28 cm. Find the total surface area of the solid. [2006] Sol. Q. 15. A toy is in the shape of a right circular cylinder with a hemisphere on one end and a cone on the other. The radius and height of the PR Q. 12. A cone of maximum size is carved out from a cube of edge 14 cm. Find the surface area of the cone and of the remaining solid left out after the cone carved out. Sol. Diameter of the cone = 14 cm = 625 cm = 25 cm ? Total surface area of the toy = Curved surface area of the hemisphere + Curved surface area of the cone = 2? r2 + ? rl = ? r (2r + l) =Radius of the each hemisphere = base radius of the cylinder = 14 cm Total height of the toy = 58 cm ? Height of the cylinder = [58 – (14 + 14)] cm = 30 cm ? Total surface area of the solid = 2? r2 + 2? rh + 2? r2 = 2? r (2r + h) 22 =2? ? 14 (2 ? 14 + 30) cm2 7 = 88 ? 58 cm2 = 5104 cm2. AK 22 ? 7 (14 + 25) cm = 858 cm2. 7 HA N Height of the toy = 31 cm Base radius of the cone = radius of the hemisphere = 7 cm ? Height of the cone = (31 – 7) cm = 24 cm r 2 ? h2 72 ? 242 cm 49 ? 576 cm cylindrical part a re 5 cm and 13 cm respectively. The radii of the hemisphercial and conical parts are the same as that of the cylindrical part.Find the surface area of the toy if the total height of the toy is 30 cm. [2002] Sol. = 2? r2 + 2? rh + ? rl = ? r (2r + 2h + l ) = = 22 ? 5 (2 ? 5 + 2 ? 13 + 13) cm2 7 22 ? 5 ? 49 cm2 = 770 cm2. 7 TH PRACTICE EXERCISE 13. 1 A Choose the correct option (Q 1 – 7) : 1. A funnel is the combination of : (a) a cone and a cylinder (b) frustrum of a cone and a cylinder (c) a hemisphere and a cylinder (d) a hemisphere and a cone. 2. A plumbline (shahul) is the combination of : (a) a cone and a cylinder (b) a hemisphere and a cone (c) frustrum of a cone and a cylinder (d) a sphere and a cylinderO ER = 144 ? 25 cm = 13 cm. Total surface area of the toy = curved surface area of the hemisphere + curved surface area of the cylinder + curved surface area of the cone BR 3. A shuttle cock used for playing badminton has the shape of the combination of : [2011 (T-II)] ( a) a cylinder and a cone (b) a cylinder and a hemisphere (c) a sphere and a cone (d) frustrum of a cone and a hemisphere 4. The height of a conical tent is 14 m and its floor area is 346. 5 m2. The length of 1. 1 m wide 7 G O YA L S canvas required to built the tent is : (a) 490 m (b) 525 m (c) 665 m (d) 860 m 5.The ratio of the total surface area to the lateral surface area of a cylinder with base diameter 160 cm and height 20 cm is : (a) 1 : 2 (b) 2 : 1 (c) 3 : 1 (d) 5 : 1 6. The radius of the base of a cone is 5 cm and its height is 12 cm. Its curved surface area is : (a) 30? cm2 (b) 65? cm2 2 (c) 80? cm (d) none of these 7. A right circular cylinder of radius r cm and height h cm (h > 2r) just encloses a sphere of diameter : (a) r cm (b) 2r cm (c) h cm (d) 2h cm 8. Two identical solid hemispheres of equal base radius r cm are stuck together along their bases. The total surface area of the combination is 6? r2. Is it true? PR Slant height of the cone = 122 ? 52 cm = 22 ? 612. 75 cm2 = 1925. 78 cm2. 7 ? Required cost of painting = Rs 5. 25 ? 1925. 78 = Rs 1010. 38. AK Radius of the cone = Radius of the cylinder = radius of the hemisphere = 5 cm. Total height of the toy = 30 cm Height of the cylinder h = 13 cm ? Height of the cone = [30 – (13 + 5)] cm = 12 cm. Internal radius (r) of the vessel = 12 cm Total surface area of the vessel = 2? R2 + 2? r2 + ? (R2 – r2) = [2 ? (12. 5)2 + 2 ? 122 + (12. 52 – 122)] cm 2 = [312. 5 + 288 + 12. 25] cm 2 AS HA Q. 16. The internal and external diameters of a hollow hemispherical vessel are 24 cm and 25 cm respectively.If the cost of painting 1 cm2 of the surface area is Rs 5. 25, find the total cost of painting the vessel all over. [2001] Sol. External radius (R) of the vessel = 12. 5 cm N ER 16. A rocket is in the form of a cone of height 28 cm, surmounted over a right circular cylinder of height 112 cm. The radius of the bases of cone and cylinder are equal, each being 21 cm. Find the total surface area of the rocket. ? ? = ? ? ? ? 7? 22 G 13. 2 VOLUME OF A COMBINATION OF SOLIDS 1. Volume of a cuboid of dimensions l, b and h = l ? b ? h. 2. Volume of a cube of edge l = l3. 3. Volume of a cylinder of base radius r and height h = ? 2h. O YA L BR 4. Volume of a cone of base radius r and height 1 h = ? r2h. 3 4 3 5. Volume of a sphere of radius r = ? r . 3 2 6. Volume of a hemisphere of radius r = ? r3. 3 TEXTBOOK’S EXERCISE 13. 2 22 . 7 O TH Unless stated otherwise, take ? = Q. 1. A solid is in the shape of a cone standing on a hemisphere with both their radii being equal to 1 cm and the height of the cone is equal to its radius. Find the volume of the solid in terms of . 8 S PR Sol. AK 9. A solid cylinder of radius r and height h is placed over other cylinder of same height and radius. The total surface area of the shape formed is 4? h + 4? r2. Is it true? 10. A solid ball is exactly fitted inside the cubical box of side a. Surface area of the ball is 4? a2. Is it true? 11. From a solid cylinder whose height is 2. 4 cm and diameter 1. 4 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid to the nearest cm2. 12. A decorative block shown below, is made of two solids – a cube and a hemisphere. The base of the block is a cube with edge 5 cm, and the hemisphere fixed on the top has a diameter 4. 2 cm. Find the total surface area of the block. 22 ? ? = ? . ? 7? [2011 (T-II)] 3. A tent of height 3. 3 m is in the form of a right circular cylinder of diameter 12 m and height 2. 2 m, surmounted by a right circular cone of the same diameter. Find the cost of canvas of the tent at the rate of Rs 500 per m2. 15. A solid is composed of a cylinder with hemispherical ends. If the whole length of the solid is 108 cm and the diameter of hemispherical ends is 36 cm, find the cost of polishing the surface at the rate of 7 paise per cm2. AS HA 14. Three cubes each of side 5 cm are joined end to end. Find the surface area of the resulting cuboid. N O YA L BR O 1 ? 3 ? 2 cm = ? cm3. 3 3 ? Q. 2.Rachel, an engineering student, was asked to make a model shaped like a cylinder with two cones attached at its two ends by using a thin aluminium sheet. The diameter of the model is 3 cm and its length is 12 cm. If each cone has a height of 2 cm, find the volume of air contained in the model that Rachel made. (Assume the outer and inner dimensions of the model to be nearly the same. ) Sol. = ? ?+ ? TH For conical portion : Radius of the base (r) = G Height of cone (h1) = 2 cm 3 cm = 1. 5 cm 2 1 2 ? r h 3 9 We know that, volume of cone = ER 22 3 cm = 66 cm3 7 Hence, the volume of the air contained in the model that Rachel made is 66 cm3. 21 ? S Q. 3. A gulab jamun, contained sugar syrup up to about 30% of its volume. Find approximately how much syrup would be found in 45 gulab jamuns, each shaped like a cylinder with two hemispherical ends with length 5 cm and diameter 2. 8 cm (see figure). [2011 (T-II)] Sol. Gulab jamun is in the shape of cylinder with two hemispherical ends. Diameter of cylinder = 2. 8 cm ? Radius of cylinder = 1. 4 cm Height of cylindrical part = (5 – 1. 4 – 1. 4) cm = (5 – 2. 8) cm = 2. 2 cm PR AK AS Radius of the hemisphere = Radius of cone = 1 cm Height of cone = h = 1 cm 2 2 ? Volume of hemisphere = ? r3 = ? (1)3 cm3 3 3 2 = ? m3 .. (i) 3 1 1 ? Volume of cone = ? r2h = ? (1)2 (1) cm3 3 3 1 = ? cm3 .. (ii) 3 Volume of the solid = Volume of the hemisphere + Volume of cone Volume of cone OAB = = 1 2 ? r h1 3 1 (1. 5)2 (2) ? cm3 = 1. 5? cm3 †¦ (i) 3 1 Volume of cone A? B? O? = ? r2h1 3 1 = (1. 5)2 ? (2) ? cm3 = 1. 5? cm3 †¦ (ii) 3 For cylindrical portion : Radius of the base (r) = 1. 5 cm Height of cylinder h2= 12 cm – (2 + 2) cm = 8 cm ? Volume of cylinder = ? r2h2 = ? (1. 5)2 (8) cm3 = 18? cm3 .. (iii) Adding equations (i), (ii) and (iii), we have Total volume of the model = volume of the two co nes + volume of the cylinder. = 1. 5? cm3 + 1. ? cm3 + 18? cm3 = 21? cm3 HA N Volume of a gulab jamun 2 2 = ? (1. 4)3 cm3 + ? (1. 4)2 (2. 2) cm3 + ? (1. 4)3cm3 3 3 = = 1 22 14 3 ? ? 0. 25 ? cm 3 7 10 ER 4 = ? (1. 4)3 cm3 + ? (1. 4)2 (2. 2)cm3 3 ? 4 ? 1. 4 ? ? 2. 2 ? cm3 = ? (1. 4)2 ? 3 ? ? ? 5. 6 ? 6. 6 ? = ? (1. 96) ? ? cm3 3 ? ? ? (1. 96) (12. 2) = cm3 3 ? Volume of 45 gulab jamuns ? (1. 96) (12. 2) = 45 ? cm3 3 = 15? (1. 96) (12. 2) cm3 22 ? 1. 96 ? 12. 2 cm3 = 15 ? 7 = 15 ? 22 ? 0. 28 ? 12. 2 = 1127. 28 cm3 30 ? Volume of syrup = 1127. 28 ? cm3 100 = 338. 184 = 338 cm3 (approximately) 11 cm3 30 ? Volume of four conical depressions 11 3 22 3 cm = cm = 1. 7 cm3 30 15 ? Volume of the wood in the pen stand = (525 – 1. 47) cm3 = 523. 53 cm3. =4? S PR Q. 5. A vessel is in the form of an inverted cone. Its height is 8 cm and the radius of its top, which is open, is 5 cm. It is filled with water up to the brim. When lead shots, each of which is a sphere of radius 0. 5 cm are drop ped into the vessel, one-fourth of the water flows out. Find the number of lead shots dropped in the vessel. Sol. Radius of cone = 5 cm Height of cone = 8 cm Volume of cone = = AK = = O YA L BR Q. 4. A pen stand made of wood is in the shape of a cuboid with four conical depressions to hold pens.The dimensions of the cuboid are 15 cm by 10 cm by 3. 5 cm. The radius of each of the depressions is 0. 5 cm and the depth is 1. 4 cm. Find the volume in the entire stands. (See figure). TH O Radius of spherical lead shot, r1 = 0. 5 cm ? Volume of a spherical lead shot G Sol. Length of cuboid, l = 15 cm Width of cuboid, b = 10 cm Height of cuboid, h = 3. 5 cm Volume of the cuboid = 15 ? 10 ? 3. 5 cm3 = 525 cm3 Volume of a conical depression = 4 3 4 ? 3 ? r = ? (0. 5)3 cm3 = cm 3 1 3 6 ? Volume of water that flows out = 1 ? (0. 5)2 (1. 4) cm3 3 10 AS 1 ? volume of the cone 4 1 ? 200? ? 50? cm3 ? ? = 4? 3 ? 3 HA 2 1 ? r h = ? (5)2 8 cm3 3 3 200 ? cm3 3 N Let the number of lead shots dropped in the vessel be n. Volume of n lead shots = As per condition, ? n? cm3 6 n? 50? = 6 3 = 31680? cm3 + 3840 cm3 = 35520 cm3 = 35520 ? 3. 14 cm3 = 111532. 8 cm3 ? Mass of the pole = 111532. 8 ? 8 g = 892262. 4 g = 892. 26 kg Hence, the mass of the pole is 892. 26 kg (approximately). BR O TH ER S Sol. Diameter of cylinder ABCD = 24 cm 24 cm3 2 = 12 cm Height of cylinder ABCD (h) = 220 cm ? Volume of cylinderABCD = ? r2h = (12)2 (220)cm3 = 31680? cm3 Base radius of cylinder A? B? C? D? , R = 8 cm Height of cylinder A? B? C?D? (H) = 60 cm ? Volume of cylinder A? B? C? D? = ? R2h = (8)2 (60) cm3 = 3840? cm3 ? Volume of solid iron pole = Volume of the cylinder ABCD + Volume of the cylinder A? B? C? D? Base radius of cylinder ABCD, r = YA L PR Q. 6. A solid iron pole consist of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8 g mass. (Use ? = 3. 14) Radius of the cone OAB (r) = 60 cm Height of cone OAB (h1) = 120 cm ? Volume of cone OAB 1 2 1 ? r h1 = ? (60)2 (120) cm3 3 3 = 144000? m3 Radius of the hemisphere (r) = 60 cm = ? Volume of hemisphere = = = Radius of the cylinder (r) = Height of cylinder (h2) = ? Volume of cylinder = 11 G O AK AS 50? 6 ? ? n = 3 ? ? n = 100 Hence, the number of lead shots dropped in the vessel is 100. Q. 7. A solid consisting of a right circular cone of height 120 cm and radius 60 cm standing on a hemisphere of radius 60 cm is placed upright in a right circular cylinder full of water such that it touches the bottom. Find the volume of water left in the cylinder, if the radius of the cylinder is 60 cm and its height is 180 cm. Sol. HA N 2 3 ? r 3 2 ? (60)3 cm3 3 144000? m3 60 cm 180 cm ? r2h2 So, r = OTHER IMPORTANT QUESTIONS Q. 1. Volume of the largest right circular cone that can be cut out from a cube of edge 4. 2 cm is : (a) 9. 7 cm3 (b) 77. 6 cm3 3 (c) 58. 2 cm (d) 19. 4 cm3 O TH YA L BR O Sol. (d) Radius of the cone = 4. 2 cm = 2. 1 cm. 2 ER 8. 5 cm 2 S Sol. Diameter of sphere = 8. 5 cm 4 ? 3. 14 ? 4. 25 ? 4. 25 ? 4. 25 cm3 + 8 ? 3. 14 cm3 3 = 321. 39 cm3 + 25. 12 cm3 = 346. 51 cm3 = Hence, she is correct. The correct volume is 346. 51 cm3. remains unfilled. Then the number of marbles that the cube can accommodate is : (a) 142296 (b) 142396 (c) 142496 (d) 142596 Sol. a) Volume of the cube = 223 cm3 = 10648 cm3 Space which remains unfilled G Height of the cone = 4. 2 cm. 1 ? Volume of the cone= ? r2h 3 = PR Q. 8. A spherical glass vessel has a cylindrical neck 8 cm long, 2 cm in diameter; the diameter of the spherical part is 8. 5 cm. By measuring the amount of water it holds, a child finds its volume to be 345 cm3. Check whether she is correct, taking the above as the inside measurements, and ? = 3. 14. Amount of water it holds = 4 ? 8. 5 ? ? ? ? cm3 + ? 12 (8) cm3 3 ? 2 ? 10648 cm3 = 1331 cm3 8 Remaining space = (10648 – 1331) cm3 = = 9317 cm3 1 22 ? ? 2. 1 ? 2. 1 ? . 2 cm3 = 19. 404 cm3. 3 7 Q. 2. A hollow cube of internal edge 22 cm is filled with spherical marbles of diameter 0. 5 cm and it is assumed that 1 space of the cube 8 12 4 ? (0. 25)3 cm3 3 Let n marbles can be accommodated. Volume of 1 marble = Then, n ? AK 3 4 22 ? ? (0. 25)3 = 9317 3 7 AS HA = ? (60)2 (180) cm3 = 648000? cm3 ? Volume of water left in the cylinder = Volume of the cylinder – [Volume of the cone + Volume of the hemisphere] = 648000? cm3 – [144000? + 144000? ] cm3 = 648000 cm3 – 288000? cm3 = 360000 cm3 360000? = m3 = 0. 36? m3 100 ? 100 ? 100 22 3 = 0. 36 ? m = 1. 131 m3 (approx. 7 Radius of cylindrical neck = 1 cm Height of cylindrical neck = 8 cm N ?n= 9317 ? 3 ? 7 4 ? 22 ? (0. 25) 3 = 142296. Q. 3. A medicine capsule is in the shape of a cylinder of diameter 0. 5 cm with two hemispheres stuck to each of its ends. The length of entire capsule is 2 cm. The capacity of the capsule is : (a) 0. 36 cm3 (c) 0. 34 cm3 Sol. (a) (b) 0. 35 cm3 ( d) 0. 33 cm3 Q. 5. The volume of a sphere (in cu. cm) is equal to its surface area (in sq. cm). The diameter of the sphere (in cm) is : [2011 (T-II)] (a) 3 (b) 6 (c) 2 (d) 4 4 3 ? r = 4? r 2 3 ? r = 3 ? d = 2r = 2 ? 3 = 6 cm Sol. (b) BR = 22 ? ? ? (0. 25)2 ? ? 0. 25 ? 1. 5? cm3 3 7 ? ? O TH Height of the cylindrical part = (2 – 0. 5) cm = 1. 5 cm Radius of each hemispherical part = Radius of the cylindrical part = 0. 25 cm. ? Capacity of the capsule 4 ? 4 ? = ? r3 + ? r2h = ? r2 ? r ? h ? 3 ? 3 ? Q. 7. The ratio between the radius of the base and the height of the cylinder is 2 : 3. If its volume is 1617 cm3, the total surface area of the cylinder is : [2011 (T-II)] (a) 208 cm2 (b) 77 cm2 (c) 707 cm2 (d) 770 cm2 Sol. (d) Let the radius and height of the cylinder be 2x and 3x respectively. Then, volume of the cylinder = ? r2h 22 ? 1617 = ? 2x)2 ? 3x 7 YA L = 22 ? 5. 5 ? ? (0. 25)2 ? ? cm3 = 0. 36 cm3 7 ? 3 ? ER Q. 4. A solid piece of iron in the form of a cuboid of dimensions 49 cm ? 33 cm ? 24 cm is moulded to form a solid sphere. The radius of the sphere is : [2011 (T-II)] (a) 25 cm (b) 21 cm (c) 19 cm (d) 23 cm Sol. (b) Volume of sphere = Volume of cuboid S PR 4 3 ? r1 r 8 2 3 = ? 1 = 4 3 27 r2 3 ? r 3 2 ? Ratio between surface areas = 4 : 9 1617 ? 7 343 = 22 ? 4 ? 3 8 ? x = 3. 5 cm. ? Total surface area of the cylinder = 2? r (h + r) ? x3 = G O AK ? 4 3 ? r = (49 ? 33 ? 24) cm3 = 38808 cm3 3 38808 ? 3 ? 7 cm 3 = 9261 cm 3 4 ? 22 ? r3 = r = 21 cm Q. 8. On increasing each of the radius of the base and the height of a cone by 20%, its volume will be increased by : (a) 25% (b) 40% (c) 50% (d) 72. 8% 13 AS Q. 6. The ratio of the volumes of two spheres is 8 : 27. The ratio between their surface areas is : [2011 (T-II)] (a) 2 : 3 (b) 4 : 27 (c) 8 : 9 (d) 4 : 9 Sol. (d ) 22 ? 7 (10. 5 + 7) cm2 7 = 44 ? 17. 5 cm2 = 770 cm2. =2? HA N Sol. (d) Volume of the original cone = New radius New height 1 2 ? r h 3 = 6r 120r = = 5 100 6h 120h = = 5 100 2 4 3 3 2 3 ? = = 3 2? 2? 2? 6: ? 2? 3 ? = 6 ? Hence, ratio of the volume of sphere to that of cube = cm. Then, volume of the metallic solid cylinder of 91 2 ? r h. 375 ? Per cent increase in volume = AK ? 216 ? 125 ? 2 = ? ? ? r h ? 375 ? height 10 = BR Q. 9. A sphere and a cube have the same surface. Show that the ratio of the volume of sphere to that of the cube is 6: ? O 91? 100 ? 3 = 72. 8%. 375 TH ER = 91 2 100 ? r h ? 1 2 375 ? r h 3 2 cm. 3 = Volume of the metal in the spherical shell 32 4 2 = ? 53 ? 33 ? r ? 3 3 32 2 4 r = (125 ? 27) ? 3 3 3 4 ? ? 98 ? r2 = 32 3 49 7 ? r = cm ? r2 = 4 2 Hence, the diameter of the base of the cylinder AS ( Increase in volume = 72 2 1 ? r h – ? r2h 3 125 2011 (T-II)] Sol. Let the radius of the sphere be r and the edge YA L O of the cube be x. Whole surface area of sphere = 4? r2 and whole surface area of cube = 6Ãâ€"2. According to question, ? S Q. 11. A solid ball is exactly fitted inside the cubical box of side a. The volume of the ball is 4 3 ? a . Is it true? 3 PR = 7 cm. Sol. Diameter of the ball = side of the cube ? Radius of the ball = ? Volume of the ball = G 4? r2 = 6Ãâ€"2. r2 x 2 = 6 3 r = ? = 4? 2? x 3 2? 4 3 ? r Volume of sphere 3 Now, = Volume of cube x3 = Hence, the statement is false. 4 ? r? 4 ? r? r ? = ? ? 3 ? x? 3 ? x? x 3 2 Q. 12.From a solid cube of side 7 cm, a conical cavity of height 7 cm and radius 3 cm is hollowed out. Find the volume of the remaining solid. 14 HA ) a 2 1 ? 6r ? 6h New volume = ? ? ? ? 3 ? 5 ? 5 72 2 = ? r h. 125 Q. 10. The internal and external radii of a hollow spherical shell are 3 cm and 5 cm respectively. If it is melted to form a solid 2 cylinder of height 10 cm, find the diameter of 3 the cylinder. [2011 (T-II)] Sol. Let the radius of the base of the cylinder be 4 a3 ? a3 = 3 8 6 N Sol. Volume of the cube = 73 cm3 = 343 cm3 Sol. 1 ? ? 32 ? 7 cm3 3 = 66 cm3 ? Volume of the remaining solid = (343 – 66) cm3 Volume of the cone = = 277 cm3.AK = = Q. 13. The difference betw een the outer and inner curved surface areas of a hollow right circular cylinder 14 cm long is 88 cm2. If the volume of metal used in making cylinder is 176 cm3, find the outer and inner diameters of the cylinder. [2010] Sol. Let the inner and outer radii of the cylinder be r cm and R cm respectively. Then, the height of the cylinder = 14 cm. Inner surface of the cylinder = 2? r ? 14 cm2 = 28? r cm2 Outer surface of the cylinder = 2? R ? 14 cm2 = 28? R cm2 Difference of the two surfaces = (28? R – 28? r) ? 88 = 28? (R – r) ? AS Radius of the hemispherical portion = 5 cm = radius of the cone. Height of the conical portion = (10 – 5) cm = 5 cm. Capacity of the shape = PR TH (R – r) = 88 ? 7 =1 28 ? 22 ER 1 2 ? r (2r + h) 3 1 22 = ? ? 5 ? 5 (2 ? 5 + 5) cm3 3 7 2750 22 ? 25 = ? 15 cm3 = cm3. 7 21 ? R–r= 1 †¦ (i) Volume of the metal used in making the cylinder = ? (R2 – r2) ? 14 cm3 . .. 176 = ? (R + r) (R – r) ? 14 BR O S 1 2750 ? cm 3. 6 7 ? Required volume of the ice cream Space which remains unfilled = ? 2750 2750 ? ? = ? ? cm3 6? 7 ? ? 7 2750 5 ? cm3 = 327. 4 cm3. 7 6 ? ? (R + r) = YA L 176 ? 7 =4 22 ? 1 ? 14 †¦ (ii) R = 2. 5 cm and G Solving (i) and (ii), we have r = 1. cm Hence, inner and outer diameters of the cylinder are 3 cm and 5 cm respectively. Q. 14. An ice cream cone, full of ice cream is having radius 5 cm and height 10 cm as shown. Calculate the volume of ice cream provided that its 1 part is left unfilled with ice cream. 6 O R+r= 4 Q. 15. A solid toy is in the form of a hemisphere surmounted by a right-circular cone. The height of the cone is 4 cm and the diameter of the base is 8 cm. Determine the volume of the toy. If a cube circumscribes the toy, then find the difference of the volumes of cube and the toy. Also, find the total surface area of the toy. Sol.Volume of the toy = Volume of the cone + Volume of the hemisphere = 1 2 2 1 ? r h + ? r3 = ? r2 (h + 2r) 3 3 3 15 HA 2 3 1 2 ? r + ? r h 3 3 N = 1 22 1408 ? ? 4 ? 4 (4 + 8) cm3 = cm3. 3 7 7 Sol. Capacity of the box = 16 ? 8 ? 8 cm3 = 1024 cm3 Volume of the 16 glass spheres 4 = 16 ? ?r3 3 4 22 = 16 ? ? ? 2 ? 2 ? 2 cm3 3 7 11264 = cm3 21 Volume of water filled in the box 11264 ? ? 10240 = ? 1024 ? cm3 ? cm3 = 21 ? ? 21 A cube circumscribes this toy, hence edge of the cube = 8 cm. Volume of the cube = 83 cm3 = 512 cm3 ? Required difference in the volumes of the toy and the cube = 487. 61 cm3. 1408 ? ? = ? 512 ? ? cm3 7 ? ? 2176 cm3 = 310. 6 cm3. 7 Total surface area of the toy = curved curface area of the cone + curved surface area of the hemisphere = 2 2 2 = ? r h ? r ? 2? r 2 ? 2 ? = ? r ? h + r + 2 r ? ? ? = YA L 22 ? 4 ? 16 ? 16 ? 2 ? 4 ? cm2 ? ? 7 BR O TH ER diameter of the dome is equal to its total height above the floor, find the height of the building. [2001] Sol. Let the internal height of the cylindrical part be h and the internal radius be r. Then, total height of the building =h+r Also, 2r = h + r ? h = r. Now, volume of the building = Volume of the cylindrical part + Volume of the hemispherical part ? ? ? ? S PR and contains 41 O 22 ? 4 ? ? 4 2 ? 8 ? cm2 = ? 7 88 ? 4 = 7 ? 2 ? 2 cm2 ? G 88 ? 4 = ? 3. 41 cm2 = 171. 47 cm2. 7 Q. 16. 16 glass spheres each of radius 2 cm are packed into a cubical box of internal dimensions 16 cm ? 8 cm ? 8 cm and then the box is filled with water. Find the volume of water filled in the box. 16 880 ? 3 ? 7 =8 21? 5 ? 22 ? r =2 Hence, height of the building = h + r r3 = = (2 + 2) m = 4 m. AK 41 Q. 17. A building is in the form of a cylinder surmounted by a hemispherical valuted dome 19 m3 of air. If the internal 21 2 880 = ? r3 + ? r3 [? r = h] 3 21 5? r 3 880 = 21 3 AS 2 19 = ? r2h + ? r3 3 21 HA N Q. 18. A godown building is in the form as shown in the figure.The vertical cross section parallel to the width side of the building is a rectangle 7 m ? 3 m, mounted by a semicircle of radius 3. 5 m. The inner measurements of the cuboidal portion of the bu ilding are 10 m ? 7 m ? 3 m. Find the volume of the godown and the total interior surface area excluding the floor 22 ? ? (base). ? ? = ? . ? 7 ? ? 1 2? = 2 ? ?r ? = ? r2 ? 2 ? 22 ? (3. 5) 2 m2 = 38. 5 m2 7 Total interior surface area excluding the base floor = area of the four walls = = 250. 5 m2. Sol. The godown building consists of cuboid at the bottom and the top of the building is in the form of half of the cylinder.Length of the cuboid = 10 m, Breadth of the cuboid = 7 m Height of the cuboid = 3 m Volume of the cuboid = lbh = 10 ? 7 ? 3 m3 = 210 m3. Radius of the cylinder = 3. 5 m Length of the cylinder = 10 m 1 2 Volume of the half of the cylinder = ? r h 2 1 22 = ? ? (3. 5)2 ? 10 m3 2 7 = 192. 5 m3 Volume of the godown = volume of the cuboid + volume of the half cylinder = (210 + 192. 5) m3 = 402. 5 m3 Interior surface area of the cuboid = Area of four walls = 2 (l + b) h = 2(10 + 7) 3 m2 = 102 m2 Interior curved surface area of half of the cylinder 22 = ? rh = ? 3. 5 ? 10 m 2 = 110 m2 7 YA L BR O TH ER Q. 19.A tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are 2. 1 m and 4 m respectively and the slant height of the top is 2. 8 m, find the area of canvas used for making the tent. Find the cost of the canvas of the tent at the rate of Rs 550 per m2. Also, find the volume of air enclosed in the tent. [2008C] Sol. O S G PR Height of the cone, H = AK ? 2. 8 ? 2 ? 22 = 7. 84 ? 4 m = 1. 95 m Area of canvas required for making the tent = Curved surface area of the tent = Curved surface area of the cylindrical part + curved surface area of the conical part = 2? rh + ? l = ? r (2h + l ) = Interior area of two semicircles 17 22 ? 2 (2 ? 2. 1 + 2. 8) m2 7 AS m HA 1 (curved surface area of the cylinder) 2 + 2 (area of the semicircle) = (102 + 110 + 38. 5) m2 + N 44 ? 7 m2 = 44 m2. 7 Cost of canvas = Rs 500 ? 44 = Rs 22000. Volume of the air enclosed in the tent = Volume of the cylindrical part + Vo lume of the conical part = = ? r2h + = = 88 8. 25 3 ? m = 34. 57 m3. 7 3 ER Q. 20. From a solid cylinder whose height is 8 cm and radius 6 cm, a conical cavity of height 8 cm and of base radius 6 cm, is hollowed out. Find the volume of the remaining solid correct to two places of decimal.Also find the total surface area of the remaining solid. (Take ? = 3. 14) [2008, 2011 (T-II)] Q. 21. A juice seller serves his customers using a glass as shown in the figure. The inner diamater of the cylindrical glass is 5 cm, but the bottom of the glass has a hemispherical portion raised which reduces the capacity of the glass. If the height of the glass is 10 cm, find the apparent capacity of the glass and its actual capacity. (Use ? = 3. 14) [2009] Sol. Radius of the cylindrical glass r = 2. 5 cm Radius of the cylinder = radius of the cone = 6 cm. Height of the cylinder = height of the cone = 8 cm. Volume of the remaining solid 1 2 = ? 2h – ? r2h = ? r2h 3 3 2 = ? 3. 1416 ? 36 ? 8 cm3 3 = 603. 19 cm3 Slant height of the cone, l O YA L BR O TH Sol. G S Q. 22. A cylindrical vessel with internal diamater 10 cm and height 10. 5 cm is full of water. A solid cone of the diameter 7 cm and height of 6 cm is completely immersed in water. Find the volume of (i) water displaced out of the cylindrical vessel. (ii) water left in the cylindrical vessel. [Take ? = 18 PR Height of the glass = 10 cm Apparent capacity of the glass = ? r2h = 3. 14 ? 2. 5 ? 2. 5 ? 10 cm3 = 196. 25 cm3 Volume of the hemispherical portion 2 2 = ? r3 = ? 3. 14 ? 2. 5 ? 2. 5 ? 2. 5 cm3 3 3 = 32. 71 cm3 ?Actual capacity of the glass = (196. 25 – 32. 71) cm3 = 163. 54 cm3. AK AS 22 ] 7 HA 1. 95 ? 22 ? ? 22 ? 2. 1 ? m3 3 ? 7 ? ? N H? 1 2 ? ?r H = ? r2 ? ? h ? ? 3? 3 ? = 36 ? 64 cm = 10 cm Total surface area of the remaining solid = curved surface area of the cylinder + area of top + curved surface area of the cone = 2? rh + ? r2 + ? rl = ? r (2h + r + l) = 3. 14 ? 6 (16 + 6 + 10) cm2 = 18. 84 ? 32 cm2 = 602. 88 cm2. = r 2 ? h2 [2009] Sol. Radius of the cylinder, r = 5 cm Height of the cylinder, h = 10. 5 cm Capacity of the vessel = ? r2h 22 = ? 5 ? 5 ? 10. 5 cm3 = 825 cm3 7 1 Volume of the cone = ? r2h 3 1 22 = ? ? 3. 5 ? 3. 5 ? 6 cm3 = 77 cm3. 7 (i) Water displaced out of the cylinder = Volume of the cone = 77 cm3 (ii) Water left in the cylindrical vessel = Capacity of the vessel – Volume of the cone = (825 – 77) cm3 = 748 cm3. 10 cm, 5 cm and 4 cm. The radius of each of the conical depressions is 0. 5 cm and depth is 2. 1 cm. The edge of the cubical depression is 3 cm. Find the volume of the wood in the entire stand. Sol. Volume of a cuboid = 10 ? 5 ? 4 cm3 = 200 cm3. Volume of the conical depression Choose the correct option (Q 1 – 5) : 1. The surface area of a sphere is 154 cm2. The volume of the sphere is : 2 1 (a) 179 cm3 (b) 359 cm3 3 2 2 3 1 (c) 1215 cm (d) 1374 cm3 3 3 2.The ratio of the volumes of two spheres is 8 : 27. The ratio between their surfa ce areas is : (a) 2 : 3 (b) 4 : 27 (c) 8 : 9 (d) 4 : 9 3. The curved surface area of a cylinder is 264 m2 and its volume is 924 m3. The height of the cylinder is : (a) 3 m (b) 4 m (c) 6 m (d) 8 m 4. The radii of the base of a cylinder and a cone of same height are in the ratio 3 : 4. The ratio between their volumes is : (a) 9 : 8 (b) 9 : 4 (c) 3 : 1 (d) 27 : 16 TH ER PRACTICE EXERCISE 13. 2A 5. The capacity of a cylindrical vessel with a hemispherical portion raised upward at the bottom as shown in the figure is : (a) ? 2h (b) ? r 2 ? 3h ? 2r ? 3 ? r 2 ? 3h ? 2r ? (c) 3 YA L BR O S 6. Two solid cones A and B are placed in a cylindrical tube as shown in the figure. The ratio of their capacities is 2 : 1. Find the heights and capacities of the cones. Also, find the volume of the remaining portion of the cylinder. G O 7. Marbles of diameter 1. 4 cm are dropped into a cylindrical beaker of diameter 7 cm containing 19 PR Q. 23. A pen stand made of wood is in the shape of a cuboid with fo ur conical depressions and a cubical depression to hold pens and pins respectively. The dimensions of the cuboid are 4 22 ? ? (0. 5)2 ? 2. cm3 3 7 = 2. 2 cm3 Volume of cubical depression = 33 cm3 = 27 cm3. ? Volume of wood in the entire stand = [200 – (2. 2 + 27)] cm3 = 170. 8 cm3. = (d) ?r 3 (3h + 4r ) 3 AK AS HA 1 2 1 22 ? r h = ? ? (0. 5)2 ? 2. 1 cm3 3 3 7 Volume of 4 conical depressions = N 11. An ice cream cone consists of a right circular cone of height 14 cm and the diameter of the circular top is 5 cm. It has a hemispherical scoop of ice cream on the top with the same diameter as of the circular top of the cone. Find the volume of ice cream in the cone. 12. A solid toy is in the form of a hemisphere surmounted by a right circular cone.Height of the cone is 2 cm and the diameter of the base is 4 cm. If a right circular cylinder circumscribes the toy, find how much more space it will cover. [2011 (T-II)] 13. A cylindrical tub of radius 12 cm contains water to a depth of 20 cm. A spherical iron ball is dropped into the tub and thus the level of water is raised by 6. 75 cm. What is the radius of the ball? 13. 3 CONVERSION OF SOLID FROM ONE SHAPE TO ANOTHER TEXTBOOK’S EXERCISE 13. 3 22 , unless stated otherwise. 7 Q. 1. A metallic sphere of radius 4. 2 cm is melted and recast into the shape of a cylinder of Take ? = 20 G O YA L BRO TH ER S 16. A heap of rice is in the form of a cone of diameter 9 m and height 3. 5 m. Find the volume of the rice. How much canvas cloth is required to just cover the heap? 17. 500 persons are taking a dip into a cuboidal pond which is 80 m long and 50 m broad. What is the rise of water level in the pond, if the average displacement of the water by a person is 0. 04 m3. 18. A rocket is in the form of a right circular cylinder closed at the lower end and surmounted by a cone with the same radius as that of the cylinder. The diameter and height of the cylinder are 6 cm and 12 cm respectively.If the slant height of th e conical portion is 5 cm, find the total surface area and volume of the rocket. (Take ? = 3. 14) radius 6 cm. Find the height of the cylinder. Sol. Radius of sphere = 4. 2 cm ? Volume of sphere = PR some water. Find the number of marbles that should be dropped into the beaker so that the water level rises by 5. 6 cm. 8. A solid is in the form of a right circular cone mounted on a hemisphere. The radius of the hemisphere is 3. 5 cm and the height of the cone is 4 cm. The solid is placed in a cylindrical tub, full of water, in such a way that the whole solid is submerged in water.If the radius of the cylinder is 5 cm and height 10. 5 cm, find the volume of water left in the cylindrical tub. 9. The largest possible sphere is carved out from a solid cube of side 7 cm. Find the volume of the sphere. 10. A cylindrical boiler, 2 m high, is 3. 5 m in diameter. It has a hemispherical lid. Find the volume of its interior, including the part covered 22 ? ? by the lid. ? ? = ? ? 7 ? 14. From a solid cylinder of height 12 cm and base diameter 10 cm, a conical cavity with the same height and diameter is carved out. Find the volume of the remaining solid. 15.A building is in the form of a cylinder surmounted by a hemispherical dome as shown in the figure. The base diameter of the dome is equal 2 of the total height of the building. Find the 3 height of the building, if it contains 67 1 m3 of 27 to AK AS air. HA N [2011 (T-II)] 4 3 4 ? r = ? (4. 2)3 cm3 3 3 Volume of cylinder = ? R2H = ? (6)2H cm3 As per condition, Volume of the sphere = Volume of the cylinder 4 ? ? (4. 2)3 = ? (6)2H 3 ? ? Radius (r) = 7 m 2 2 Depth (h) = 20 m Volume of sphere of radius 6 cm 4 = ? (6)3 cm3 3 Volume of sphere of radius 8 cm ? †¦ (i) Hence, the height of the platform is 2. m. = As per condition, G ? ? 4 3 4 4 4 ? R = ? (6)3 + ? (8)3 + ? (10)3 3 3 3 3 3 = (6)3 + (8)3 + (10)3 R R3 = 1728 O YA L 4 3 3 ? R cm 3 BR 4 ? (10)3 cm3 †¦ (iii) 3 Let the radius of the resulting sphere be R cm. T hen volume of the resulting sphere = TH ER 4 ? (8)3 cm3 3 Volume of sphere of radius 10 cm = †¦ (ii) Q. 4. A well of diameter 3 m dug 14 m deep. The earth taken out of it has been spread evenly all around it in the shape of a circular ring of width 4 m to form an embankment. Find the height of the embankment. [2011 (T-II)] Sol. For well : S PR O †¦ (iv) 3 m 2 Depth of well (h) = 14 m ?Volume of earth taken out = ? r2h Radius of well (r) = AK H = Sol. We know that, volume of the sphere = 4 3 ? r 3 AS Q. 2. Metallic spheres of radii 6 cm, 8 cm and 10 cm, respectively, are melted to form a single solid sphere. Find the radius of the resulting sphere. 245? 245 ? 22 ? H= ? H= 2. 5 308 308 ? 7 Diameter = 3 m 63 ? 3? = ? ? ? (14) m3 = ? m3 2 ? 2? Width of the embankment = 4 m Let the height of the embankment be H m. ? Radius of the well with embankment, R ? R = 3 1728 ? R = 12 Hence, the radius of the resulting sphere is 12 cm. Q. 3. A 20 m deep well with diameter 7 m is dug and the earth from digging is

Saturday, September 28, 2019

Printing Press Consequences

The Consequences of a Forgotten Invention There have been people who have influenced every person in the world yet a seldom few know their contributions let alone their names. Of these people was a man named Johannes Gutenberg; the man who invented the printing press. The printing press is one of those inventions that most people take for granted and do not realize their importance. Without the press we would still be handwriting every single copy of any book every written and so the question is what were the main consequences of the printing press? That is, what happened as a result of the invention of the printing press?The answer is that it marked the transition from script to printing and it allowed the mass production of information, which in turn allowed ideas to spread quicker. The ability to have a mass production of information has transformed almost all aspects life and all fields of study. Two of these topics include religion and geography and exploration. This essay will first explain the importance of the transition from script to printing and then will go on to explain the impact the press had on literature and geography and exploration in order to elaborate on the latter consequence listed above.Perhaps the absolutely most important thing about the invention of the printing press is that it marked the transition from script to printing. As seen in Document A, whilst comparing the two images, the effect of Gutenberg’s invention is very clear. In the top visual, which shows the dictation method, it can be seen that the process is very lengthy and tiring. Also, only a few books are visible. Whereas, in the bottom visual, which shows the printing method, there are many papers in sight and the process seems to be a lot less time-consuming.From this it can be concluded that printing is a lot more efficient method of producing books and no longer required laborious hours of writing manuscripts. This conclusion can be supported by the next documen t: Document B. By looking at the maps it becomes apparent that the people back then also had similar opinions about the printing press as, with-in thirty years, the number of printing presses in Europe more than quintupled. In 1471, there were about a dozen presses but by the end of the century, there were upwards of 65 in the continent. However, Document C represents a contradicting opinion.This source claims that people still liked hand-written documents over those that were printed. This was bound to happen because, even like today, hand-made items are always considered more precious but the more practical solution will always prevail, which, in this case, was the printing press. In the subsequent paragraphs, the consequences of this transition on various aspects of life will be explained. ‘Gutenberg’s invention probably contributed more to destroying Christian concord and inflaming religious warfare than any of the so-called arts of war ever did. These twenty-four w ords written by Elizabeth Eisenstein in her book, ‘Printing Revolution in Early Modern Europe,’ (Document E) perfectly describe the consequence of the printing press on religion. Around the same time as the birth of the printing press, a desire for reformation in the Church was also arising amongst the people. According to history, Martin Luther lit the fire of desire by posting his 95 Theses on a Church door. However, what is not being taken into account is that Luther’s ideas spread quickly solely because of the printing press, as John Man explains in Document D.Had his ideas not spread all over Europe with-in a month, reform would have come much later or perhaps never. Similar to Luther’s 95 Theses, the Polyglot Bible, which allowed ordinary people to understand the Bible as it was written in nine different languages, would not have spread around Europe so rapidly if it were not for the press. Both, the Polyglot Bible (Document G) and Luther’s 95 Theses (Document D), fueled the Protestant reform but would not have even close to as big of an impact if it were not for the printing press.The map in Document F verifies this statement because it shows how quickly Protestant ideas spread around Europe. In merely 60 years, Europe went from being completely Catholic to roughly half Protestant and half Catholic. This in itself further emphasizes how mass production of information allows ideas to be spread faster and therefore demonstrates the one of the consequences of the printing press. Along with the religious turmoil came times of great exploration. Partially credited to Renaissance ideals, Europeans began to explore the world. Perhaps the most famous explorer of all is Christopher Columbus.In 1492, he did indeed sail the ocean blue to discover the Americas. After Columbus, came other great sailors from various other European nations who explored other parts of the world. Believe it or not, the printing press served a great purp ose in exploration too. Columbus sent a letter to the King of Spain, which talked about the New World. According to Document H, this letter was translated and published over and over again and with-in a year it reached places as far as Antwerp. In the succeeding years Europeans embarked upon a great number of voyages.This indicates that Columbus’ letter was likely to have sparked curiosity or even jealously into the hearts of other Europeans and so they to began to explore the world. There was an obvious correlation between exploration and maps. As seen in Document I, the more people that explored, the more accurate the maps were became. The relationship goes the other way too. The more accurate the maps were, the better the explorer can judge where they were, which then allowed them to have a better sense of direction. The printing press played a huge role in the publication of maps.With the press, maps now looked the same, unlike before when they were drawn by hand, which a llowed for inconsistencies amongst copies of the same work. Once again, this highlights both consequences stated above: the press allowed the mass production of information and marked the transition script to printing. In conclusion, it can be clearly seen that the printing press revolutionized the world on a countless number of levels. It transformed the way people communicated and the way information was dispersed. The transition from script to print was huge because the press was far more efficient for publishing any kind of information.As a result, there could now be a mass production of information. It was made obvious, through the examples given, how mass production fueled the Protestant Reformation and perhaps even sparked the age of exploration. Taking all this information into account there is no doubt that the consequences of the printing press were that it marked the transition from script to printing and it allowed the mass production of information, which in turn allowe d ideas and information to spread over a large distance in a short period of time.

Friday, September 27, 2019

Analyse the Strategic position of IMAX Essay Example | Topics and Well Written Essays - 2000 words

Analyse the Strategic position of IMAX - Essay Example This paper aims to analyze the current situation of IMAX and present alternative solutions to their problems. The paper involves Porter’s five forces analysis of the movie production and distribution industry. The second part enumerates and evaluates the corporate strategies of the company which are focused differentiation and growth. It has been examined that the strategies employed by the company were effective in achieving their objectives. It is the recommendation of this paper that the company prepares itself to for acquisition. The company cannot survive on its own in the film industry as they face the issues on debt and sustainability. IMAX is an entertainment technology company that generates revenues from long-term theater system lease and maintenance agreements, film production and distribution, and theater operations. It is involved the different processes of large-format film business. The company has a movie library of 226 films that were either produced by IMAX or other independent filmmakers or studios. The company has generated total revenues close to $116 million by 2007. At the end of 2008, the market capitalization is $125 million with 295 theaters showing IMAX movies in 40 countries. (IMAX Corp, 2008) An industry analysis is completed in Section 2.1 where Porter’s five forces were employed. The analysis covers competition between industry rivals in the Motion Picture and Video Distribution market segment where IMAX generates its revenues and profit. The threat of new entrants is also scrutinized for the industry. Furthermore, the bargaining powers of suppliers as well as consumers are studied with regards to its effect on the company. The threats of substitutes are investigated which are considered as alternative and indirect competition of the business. Section 2.2 attempts an internal and external analysis of IMAX which is patterned on the SWOT analysis. The growth and success of the movie industry is the

Thursday, September 26, 2019

Stuxnet virus Research Paper Example | Topics and Well Written Essays - 3000 words

Stuxnet virus - Research Paper Example The critical infrastructure of any country consists of composite, self-governing and cyber based resources, which is vital for the nation’s financial system and supervision. It is concerned with communications, transportation, water supply, energy, emergency services, and banking and finance. On the other side, vulnerabilities also emerged causing disruption to the critical infrastructure affecting in several ways. Although there are many vulnerabilities, cyber attacks are the most prominent one. Cyber attacks approach the target in a nontraditional way. Due to inequity in the military strengths, hackers attack this critical infrastructure affecting both the economy as well as the military sector of the country (SANS: Critical infrastructure protection). Economy of countries adopting a computerized critical infrastructure relies on cyber-supported infrastructures, enabling hackers to attack on the information systems and the infrastructure to damage the economy and military st rength (SANS: Critical infrastructure protection). Thousands of new cyber attacks categorized with ‘Major’ and ‘Minor’ are penetrated on the Internet daily. The focus is the power sector of the United States including websites of Poland, South Korea and United Kingdom. They all have witnessed cyber attacks in past few months. Different schools in various states of America have lost millions of fraudulent wire transfers (Shackelford, 2010). Cyber attacks are intelligent as well as organized. Once the network is hacked, they install small lop holes or software intruders for giving hackers access whenever they want to access the network again. In simple words, one can say that, it is a computer-to-computer attack to steal the confidential information, integrity or the data presently available on the network. The attack adopts a calculated approach to modify action against data, software and hardware in both computers and networks (Denning & Denning, 2010). It is essential to define a solid network defense for handling cyber attacks. The government or the private sector could operate it, both Networks provide opportunities for hackers to intrude the destination remotely and take control of the capabilities and resources these devices has. The impact of hacking in these systems is devastating. For example, hackers may gain access to the military radar systems, credit card data stolen, data stolen from the Federal Bureau of Investigation (FBI) has revealed secret agents, and now their life is at risk etc. The capacity of these attacks impact on the country’s economy, security and financial stability. They breach government networks that are directly related to national services. ‘Stuxnet’ The most destructive virus or worm was discovered in June 2010 named as ‘Stuxnet’. It was classified as a ‘worm’. Network dictionary provides a comprehensive definition of a ‘worm’ that states as à ¢â‚¬Å"A destructive program that replicates itself throughout a single computer or across a network, both wired and wireless. It can do damage by sheer reproduction, consuming internal disk and memory resources within a single computer or by exhausting network bandwidth. It can also deposit a Trojan that turns a computer into a zombie for spam and other malicious purposes. Very often, the terms "worm" and "virus" are used synonymously; however, worm implies an automatic method for reproducing

Entry strategy of IKEA in to Brazil Essay Example | Topics and Well Written Essays - 1500 words

Entry strategy of IKEA in to Brazil - Essay Example In the initial stages IKEA expanded its business into new markets outside of Sweden including Norway by direct entry and by acquiring other businesses. However, over the years IKEA has been focusing on expansion of its business through franchising. IKEA now operates over 325 stores which are located in 35 countries. An analysis of the Brazilian market indicates that it is a very promising environment for IKEAs products. The standard of living of working class individuals have improved and this has increased their demand for various products including home furnishings. Upper and middle class Brazilians have high disposable income and are willing to spend on high quality brand name products and so it would be good if IKEA offer goods for different segments of the market instead of focusing on just low priced products. Additionally, research indicates that 59% of Brazilians have a preference for foreign brands over home brands. However, there are certain obstacles in the political and legal environment that may negatively impact the success of IKEAs business. Furthermore, the currency of Brazil is overvalued. It is therefore important that IKEA use its resources to correct weaknesses in its operations and make use of opportunities and lessen the impact of threats in the environment. IKEA operates 325 stores in 35 countries throughout the world. The company’s first stores between 1955 and 1978 were opened in Sweden, Norway, Denmark, Switzerland, Germany, Australia, Hong Kong, Canada, Austria, Netherlands and Singapore. Since then the company has expended its operations to 24 additional countries. However, the company does not have a presence in Brazil. Most of IKEA stores are franchises and therefore the company does not have to provide any capital outlay. However, franchise fees are dependent on the success of its franchise operations. In

Wednesday, September 25, 2019

Environmental and Global Awareness Research Paper - 1

Environmental and Global Awareness - Research Paper Example nship of human beings with the earth is not very healthy and this makes it important for us to increase our environmental and global awareness, unless we want some serious consequences, which can affect our well being. The need for global awareness in the contemporary international community can be best understood by looking at the relationship of human beings and Mother Nature. We should try to find an answer to questions like, what are our actions towards our environment, what is the earth doing for us and what are the consequences of our actions, which makes the elevation of global and environmental awareness amongst the people essential. After understanding the consequences, we should try to bring modifications in our action to have a better future. Human beings are dependent on the earth and its ecosystem for goods and services. The goods and services are important and essential for the personal well-being of human beings. The earth is the source of all wealth — dams, ports, highways, buildings, etc. It is giving us the goods and services without taking anything in return.(Chiras 20). Earth can fulfill our needs but it cannot fulfill our greed. Its resources can fulfill our requirements but cannot last in front of our exploitation. Human beings are exploiting the biodiversity of the ocean. The development of industrial fishing and sophistication of the fishing technology is putting pressure on this â€Å"supposed- Inexhaustive aquatic resources† (Adeleye 230). Fishes and other aquatic products have declined due to the ruthless exploitation, loss of habitat by sand filling operations and pollution of wetland from oil exploration and industries. The uncontrolled trawling for fishes throughout the year has led to the extinction of some species (Adeleye 231) The harm caused by man to the ecosystem is enormous. The world’s ecosystems have deteriorated by 33% in between 1970 to 2000 and exploitation of natural resources have increased by the same amount

Tuesday, September 24, 2019

Calligraphy Box with Design of Autumn Flowers and Grasses under the Essay

Calligraphy Box with Design of Autumn Flowers and Grasses under the Sun and the Moon by Igarashi Doho from 17th century Japan - Essay Example Such artwork was unique to the dominant class of the Japanese society, although there was a difference in popularity of different art types. Art from the Edo era, as the writing box by Igarashi, comprised of several themes and styles of art, which resulted in the era being categorized as the revival era of Japanese art. Doho’s calligraphy box, as a piece of art, captures three traits of the Japanese society in the periods leading to the 17th century; religion, wealth and power, and education. The calligraphy box is popular for a number of reasons. Considering the age in which the box was crafted, the level of detail and its intricacy is indicative of developed art in the Japanese culture. The detailing on the wood and incorporation of gold and metal facilitates the development of a unique art form that appears modern as well as complex. There is awe in the artisanship employed in the decorations on the box, which suggest considerable time spent on the development of the artifact. The art could only be achievable in the presence of history and a structured discipline in where artistic skill used in the art was taught. Furthermore, the degree of preservation, considering the age of the art, is one of a civilization that incorporated science into its daily norms. Religion has a huge impact in the calligraphy box, as well as the techniques used in the artisanship. The Early Heian art, which was introduced by Buddhist priest Kukai, influenced the development of Japanese art. One of the attributes that was derived from the religion was the use of gold in art. The calligraphy box appears as having a golden cover to the wood, which is characteristic of the Heian period (Brinkley 26). The E-maki (last Heian) period further imposes the impact of religion on art, as the development of picture scrolls was introduced, with emphasis on the liveliness of the colors used as well as the narration incorporated in the art. Following the

Monday, September 23, 2019

Critique Essay Example | Topics and Well Written Essays - 500 words - 8

Critique - Essay Example The strong dialogue delivery by the actors and their performances has played a key role in making this movie an exceptional one. It is impossible to make an exceptional movie with an utmost perfection without an excellent direction and a strong story. Joel Coen and Ethan Coen have perfectly represented the deteriorated situation of law and order of New Mexico. The film contains all the elements present in a western society with no law and greater violence filled with hatred and agony that is so visible from the way the directors have represented the perfect western violated society. The movie has the perfect cinematography, editing and shot composition that together have made this movie a flawless masterpiece. Every shot is captured beautifully. For example Moss is hunting when he spots a hunting dog. Here the scene â€Å"Cuts to† the far away scene of four to five pickup trucks; with opened doors and no people in it. Then it again cut to the scene of Moss standing in between the dead bodies and the dead dog. The balance and the sequence between the shots are clearly visible. Another example of a glorious sequence is when Moss starts heading along the tire tracks which is hardly visible in the tall grass, the scene cuts to the place where Moss spots the tree where he thought that the man with the money would have stopped, then its cuts again and Moss is seen on the dead body of that man. From there is gets into his car, within a second in his home and the other second he is shown talking to his wife. The entire sequence is flawless and captivating. The movie has shown so much blood-filled scenes that may be something that few of the audience may find it hard to watch. The directors have tried their best to go with the novel without any alteration; only where it was necessary for them to change. This has enhanced the strong screenplay of the movie. The

Sunday, September 22, 2019

Drug Addiction Essay Example for Free

Drug Addiction Essay This essay will outline the main points for an addict and will serve as a guide for an addict or family of an addict. Addictions are very dangerous for a person, emotionally, psychologically, and physically. There three main points to an addiction, the actual addiction and the symptoms, the addiction cycle (downhill spiral), and how to treat or where to treat an addiction. This essay will hopefully outline the main points for an addict and will hopefully serve as a guide for an addict or family of an addict. Addiction Addiction is defined as an overuse of any substance that changes the natural chemical balance of the brain. Most addiction specialists agree that addiction includes biological, psychological, and behavioral factors. There are many opinions as to what causes an individual to become susceptible to drug addiction. Many believe there are underlying physical and mental issues that contribute to developing an addiction. There are many different causes of addiction. Regardless of how or why an addiction began, there is a definite cycle of addiction that many individuals get trapped in. This addiction cycle is often referred to as the downward spiral. Breaking the addiction cycle can be a long and difficult process, depending on the nature of the addiction. There are many different types of addiction. An addiction can be developed by anyone; it is not reserved for certain personality types, social standing, or career fields. The best defense and recovery tool against addiction is education. Individuals caught up in the addiction cycle often try to hide or disguise their addictive behavior. They even try to hide the addiction from themselves. There are certain types of behavior that can assist a loved one or family member in identifying drug addiction. Once the drug addiction is identified, it is important that someone confront or intervene with the individual suffering from the addiction. Drug Addiction Cycle A cycle, simply put, means something that goes around and around like the wheels on a bike, or a brightly painted carnival carousel. Cycles can be a positive thing such as the annual review and raise that one might receive at work, or they can be negative. When is a cycle a negative or dangerous pursuit? When it threatens to destroy a quality life. If the Earth does not have snow and rain in the winter season, it dehydrates and is parched in the summer. It starves and so do we. If the wheels on the bike stop moving, the bike and rider fall over. If an addict cannot break free from the destructive and life threatening patterns of drug and alcohol addiction, they and/or others may suffer and die needlessly and harshly. The cycle of drug addiction never has a positive outcome and all efforts should be made to achieve a healthy, productive and long-term recovery from this dark and sinister downward spiral. To recreate a new pattern of living from a torn path will be the greatest and most empowering inner expedition an addict will ever encounter. The first step is to truly want it†¦so sincerely that a person can think of little else other than getting clean. It may be for oneself, a loved one or better yet a combination of both. Unfortunately, the reality of the addiction cycle and breaking free from its grip, is not that uncomplicated. Breaking free can be a very difficult process with occasional periods of personal let down, but this fact cannot in any way be allowed to discourage those seeking freedom from drug addictions. A person’s body, in almost every aspect of its being, is addicted when one is a mild to chronic user and abuser. The nervous system, brain, and muscle tissue are all living in anticipation of the next high. So, for the addict, it is crucial that the cycle of behavior, is broken. The addict needs to pull up the anchor that keeps them from moving forward. This means changing environments, patterns and even sometimes friends and social associates. Once an addict has made the personal commitment to change old habits, the next step is to establish new, safe and positive influences in their life. These can be found in quality support groups, hospital substance abuse centers and drug rehab centers. No matter what the setting, it is important to be around strangers. Being in proximity to familiar places and people may promote the tendency to fall back into old thoughts and behaviors. Of the aforementioned options, private drug rehabilitation retreats seem to be gaining popularity, in part, due to the impressive success rate they boast. What parents should know about drug addiction Drug and substance abuse among children, especially teens, is substantial. According to the most recent statistics available, (http://www. nationalyouth. com) 1. million of our youth age 12 to 17 meet the diagnostic criteria for dependence on drugs and approximately 1 million of our American youth (http://www. drugabusestatistics. samhsa. gov/) are being treated for alcohol dependency. Although these statistics may be surprising, there are many things that parents can/should know about the prevention of drug addiction including how to recognize the signs/symptoms of drug/alcohol addiction and what they can do to help their child once a problem has been recognized. Studies have shown that parents are often the first line of defense in the prevention of drug addiction. Numerous public service commercial announcements advertise parents as â€Å"the anti-drug. † Parents need to understand that ignorance is not bliss. Parents need to be well armed with the facts on prevention and treatment. Parents need to spend quality time with their children and be open to discussions on drugs and alcohol. Parents need to know who their child’s friends are, where they are going, what they are doing, etc. Parents need to make their expectations very clear and establish that they will not tolerate drug use of any kind. If all of these factors are utilized, children will be less likely to use drugs. It is also important that parents educate themselves about the types of drugs currently available. Although some of the standard drugs (drugs that may have been popular while the parent was a youth) are still around (marijuana, LSD, etc) there are also a number of new drugs that are very popular with today’s youth such as the inhalants (huffing). Conduct research on the Internet or attend a local community meeting regarding substance abuse. There are three categories of substance abuse: Use: The occasional use of drugs without developing tolerance of withdrawal symptoms when not in use. Abuse: The continued used of drugs even while knowing that the continued use is creating problems socially, physically or psychologically. Dependence: Where three of the following factors must be present: the substance is taken in large amounts over longer periods of time; their child has an everlasting desire for the substance and has been unable to control their use; child may suffer from repeated periods of intoxication or detoxification; child continues to use even though the substance is causing problems; and the child takes more of the substance in order to relieve any withdrawal symptoms they may be experiencing. It is important for parents to note that different substances lend themselves to different groups of drug addiction symptoms. In all cases however, the most visible symptom is a radical change in behavior. If a parent suspects that their child is abusing drugs, consult with a personal physician or pediatrician, an educational consultant whose expertise is this area, an addiction therapist or a drug counselor. These professionals will help the parents assess the situation and seek the proper addiction treatment. How to Find a Drug Rehab Center The first step is to contact a Doctor or a health professional. They will be able to point a person in the direction of a good drug rehab center. It is important that they be consulted with since they know the person and a bit about their history. They also might know and understand the addiction, and therefore be able to direct the addict to a drug rehab center that can cater to specific needs. If this option does not work, try to talk to local authorities that deal with drug addiction treatment. Most places that deal in mental health or in health practices will know exactly where to find good drug rehab centers. Free clinics and walk-in addiction counseling services, will have a lot of information regarding drug rehab centers. Another place to look for drug addiction treatment is the Yellow Pages. Researching on the internet might get you more information about the drug rehab centers a person is thinking about going to. There are also many online drug rehab referral services that can assist a people in making a decision. No matter how a person goes about finding a drug rehab center, there are important things that have to be kept in mind while doing so. Does the rehab center deal with this particular drug addiction? What are the costs and are they affordable? Is this particular facility covered by insurance? Is it covered by Medicaid? In addition, keep in mind that there are many state and government drug rehab centers that are available at no cost. These might be a big help as the cost of recovery is expensive. Another very important thing to keep in mind, are the services that the drug rehab center provides. Do they have in patient services as well as out patient services? Do they have counseling sessions that one can attend after the in-patient treatment is completed? Do they have information that they can give the patient/ family to read, and do they have any services for the addict’s family and loved ones? Make sure to find out about the staff to patient ratio, and how much time is going to spent at the drug rehab center. Most importantly, one should seek a drug rehab center where one can feel safe and comfortable. An addict is going to make the most progress in a place where they feel at ease and can be themselves. Recovery is a long and hard road, and if it is done in an environment where a person can feel the most comfortable, and just be themselves, they are going to be the most successful. Getting help for an addiction is something that is not easy, but a drug rehab center is a place where it might all seem to be a little bit less difficult.

Saturday, September 21, 2019

Impact of Music on the Body

Impact of Music on the Body Music and Success Music in itself has a strong impact on the emotional state of the human body. By listening to a certain type of tone or melody, it can make us feel happy or even sad. When listening to sad music, you can become saddened by it, relating to what the lyrics say, or the type of major its in. The same happens with happy or upbeat music, you tend to want to dance or jump around, or even sing along! Not only can music change the way you feel, but it can also, in some cases, help you concentrate better. If music is capable of changing your emotions, do you think that training with it could also determine how successful you are throughout your life? Albert Einstein is known worldwide to be one of the worlds greatest minds. A master of the sciences, a wonderful mathematician, and a great philosopher. His whole life, he had grown up listening, learning, and training with music because of his mother. She was a professional pianist and his father was a salesman with a passion for mathematics. His mother thought it would be nice to get her son into learning an instrument, so the violin became the instrument of choice. Einstein grew up with a passion and love for music Life without playing music is inconceivable to me. I live my daydreams in music. I see my life in terms of music I get most joy in life out of music. (Bergland) I believe, as do others, that musical training had helped him develop certain skills sooner than he wouldve originally had in the first place. Of course, it could be because of his fathers influence of his passion for mathematics, but researchers say otherwise. There are many different kinds of benefits to musical training that are shown to be true. Musical improvisation is a type of special training that makes you rely on the working memory less, using instead more extensive connectivities to the brain. It can stimulate the area of the brain that can enhance your main senses such as touching, hearing, seeing, ect. Adult musicians and musically trained children in the new Boston study showed enhanced performance on several aspects of executive functioning. (Bergland) Musicians that have grown older have shown signs of acute hearing and enhanced and developed motor skills, being able to switch quickly from one mental task to the other. Even children who were training in instruments were tested in IQ and seemed to have a higher level of intelligence than those who did not, and naturally, a higher IQ means theres more likely of a chance for those children to become successful throughout their lives. The New Boston study was performed to test whether or not students with musical training helped them in their years of school. They decided to compare kids who had trained with instruments to those that had not, and put them through functional MRI (Functional magnetic resonance imaging) scans. The children who had been through musical training had more activity on specific parts of the brain that had been proven to help them test better. Our findings suggest that musical training may actually help to set up children for a better academic future. (Flieser) A lot of people agree that instead of schools focusing their income on standardized testing, they should put more effort into musical arts.This would not only insure a higher success rate of fellow students, but it would also boost their levels of happiness. Who wouldnt want to replace a test for a chance at learning an instrument for free? Further research has proven that music taps into other skills other than simple aspects like hands or fingers, Making music involves more than the voice or fingers playing an instrument; a child learning about music has to tap into multiple skill sets, often simultaneously. (Brown) When playing an instrument, it requires a lot of effort and multiple things must all come together at once in order to perform the correct task. You use all different kinds of muscles to perform the actions such as your arm and finger muscles when playing a violin, or your vocal chords and esophagus when singing. You also use your eyes to read the notes off of paper, having to memorize what each little note sounds like, and then using those muscles to make that certain tune. Your ears, of course, are used to listen acutely to make sure youre playing the right note. Normally, if youve trained enough, you can tell when a note sounds out of tune, so your sense of hearing between different kind of sounds would naturally be increased. Learning an instrument also help with language development. They learn to process different sort of sounds better, and are able to make out and decipher words much easier. According to researchers, the effect of language development because of music can be shown in the more active parts of the brain. It increases the rate of growth in language development. The bond between language and music help compliment each other, so if a child studies in one area, they are more than likely going to get the hang of the other just as easily, The development of language over time tends to enhance parts of the brain that help process music, says Dr. Kyle Pruett, clinical professor of child psychiatry at Yale School of Medicine and a practicing musician. (Brown) Being musical, and being around people who are musically creative, can have a positive influence on the children, encouraging them to go to higher lengths and accomplish greater things. If you have an environment where there are a lot of people doing creative, smart, great things, joyful things, even people who arent doing that have a tendency to go up and do better.(Brown) According to Luehrisen, even those who are not involved in said activities can grow up to be more successful just because of the influence of the people around them. Just giving your child the opportunity to train with an instrument does not guarantee that your child will end up turning into some famous musician, but the fact that there is a connection there that exists with success does happen to mean a lot. He says music reinforces your confidence in the ability to create. (Lipman) Music in itself is a very creative hobby, but when training with it, it has the possibility to open your mind up to more ideas. That is why people who play with instruments often begin making a little tune of their own just for fun. Improvisation exists because of this reason as well. People play from their hearts and their minds making their tunes and melodies form together like a puzzle piece. Music is a wonderful thing. It has many, many positive aspects in life if you learn to get familiar with it. You dont have to be as skillful as Beethoven in order to insure success in your life. Just learning one instrument can have a dramatic change in your life, so if you havent already, go pick up one and see what lays in store for you. Work Cited Bergland, Christopher. Does Playing a Musical Instrument Make You Smarter? Psychology Today, Psychology Today, 25 June 2015, www.psychologytoday.com/blog/the-athletes-way/201406/does-playing-musical-instrument-make-you-smarter. Brown, Laura Lewis. The Benefits of Music Education. PBS, PBS, www.pbs.org/parents/education/music-arts/the-benefits-of-music-education/. Lipman, Joanne. Is Music the Key to Success? The New York Times, The New York Times, 12 Oct. 2013, www.nytimes.com/2013/10/13/opinion/sunday/is-music-the-key-to-success.html. Fliesler, Nancy. Does Musical Training Help Kids Do Better in School? Does Musical Training Help Kids Do Better in School?, Boston Childrens Hospital, 19 June 2014, vector.childrenshospital.org/2014/06/does-musical-training-help-kids-do-better-in-school/.